14x+8=4x^2

Solution for 14x+8=4x^2 equation:

14x+8=4x^2

We move all terms to the left:

14x+8-(4x^2)=0

determiningTheFunctionDomain
-4x^2+14x+8=0

a = -4; b = 14; c = +8;
Δ = b2-4ac
Δ = 142-4·(-4)·8
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-18}{2*-4}=\frac{-32}{-8}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+18}{2*-4}=\frac{4}{-8}
=-1/2
$